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Anni [7]
3 years ago
6

Why is (3,-5) not a solution to -x+4y=-15

Mathematics
1 answer:
Olegator [25]3 years ago
3 0
C) It doesn’t satisfy either the top or bottom equations.


When we plug them into the top equation:
- 3 + 4( - 5) =  - 15
Simplify:
- 3 + ( - 20) =  - 15 \\  \\  - 23=  - 15
Because the statement of -23 = -15 is wrong, the solution pair is wrong for the top equation.


When we plug them into the bottom equation:
- 2(3) - 3( - 5) =  - 8
Simplify:
- 6 - ( - 15) =  - 8 \\  \\ 9 =  - 8
9 = -8 is not a valid statement, so the pair doesn't satisfy both of the equations.
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If I chose a number uniformly from the integers from 1 to 25, calculate the conditional probability that the number is a multipl
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Answer:

<h2>1/7</h2>

Step-by-step explanation:

If I choose a number from the integers 1 to 25, the total number of integers I can pick is the total outcome which is 25. n(U) = 25

Let the probability that the number chosen at random is a multiple of  6 be P(A) and the probability that the number chosen at random is is larger than 18 be P(B)

P(A) = P(multiple of 6)

P(B) = P(number larger than 18)

A = {6, 12, 18, 24}

B = {19, 20, 21, 22, 23, 24, 25}

The conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is expressed as P(A|B).

P(A|B) = P(A∩B)/P(B)

Since probability = expected outcome/total outcome

A∩B = {24}

n(A∩B) = 1

P(A∩B) = n(A∩B)/n(U)

P(A∩B) = 1/25

Given B = {19, 20, 21, 22, 23, 24, 25}.

n(B) = 7

p(B) = n(B)/n(U)

p(B) = 7/25

Since P(A|B) = P(A∩B)/P(B)

P(A|B) = (1/25)/(7/24)

P(A|B) = 1/25*25/7

P(A|B) = 1/7

<em></em>

<em>Hence the conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is 1/7</em>

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If f(x) = (x - 1) / (x + 2), then the range of f is given by the interval
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Answer:

B and D

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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