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3 years ago

6

Why is (3,-5) not a solution to -x+4y=-15

1 answer:

Olegator [25]3 years ago

3 0

C) It doesn’t satisfy either the top or bottom equations.

When we plug them into the top equation:
$- 3 + 4( - 5) = - 15$
Simplify:
$- 3 + ( - 20) = - 15 \\ \\ - 23= - 15$
Because the statement of -23 = -15 is wrong, the solution pair is wrong for the top equation.

When we plug them into the bottom equation:
$- 2(3) - 3( - 5) = - 8$
Simplify:
$- 6 - ( - 15) = - 8 \\ \\ 9 = - 8$
9 = -8 is not a valid statement, so the pair doesn't satisfy both of the equations.

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Mr. Bridge teaches four regular classes and a seminar. The numbers of students in his classes are: 32,29,33,8,31 What is the mos

ElenaW [278]

Answer:

32: median

Step-by-step explanation:

Use the median. Here the median is the middle value of the data string

8, 29, 32, 31, 33, that is, 32.

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3 years ago

What is 7 9/13 as an improper fraction

jasenka [17]

7 9/13
= (7×13)+9/13
= 91+9/13
= 98/13 (as an improper fraction).

6 0

3 years ago

Evaluate the function g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

Roman55 [17]

Evaluate the function

g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

This is tedious math work but necessary to sharpen your skills.

Let x = -2

g(-2) = 2(-2)^2 + 3(-2) – 5

g(-2) = 2(4) - 6 - 5

g(-2) = 8 - 11

g(-2) = -3

Now let x = 0 and repeat the process.

g(0) = 2(0)^2 + 3(0) - 5

g(0) = 0 + 0 - 5

g(0) = -5

Lastly, let x = 3.

g(3) = 2(3)^2 + 3(3) - 5

g(3) = 2(9) + 9 - 5

g(3) = 18 + 9 - 5

g(3) = 27 - 5

g(3) = 22

Did you follow through each step?

4 0

3 years ago

Identify two composite numbers that each have 8 as a factor.

Lemur [1.5K]

Two composite numbers that have 8 as a factor are 16 and 24.

7 0

3 years ago

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

4 0

3 years ago