Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is
in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:
Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths 
is
So the solution here is
Answer:
3/8, 2/5, 11/20, 23/40, 7/10, 3/4
Step-by-step explanation:
Just change them all to the same denominator and you're good. Put all of the fractions' denominators to 40 as that's the least common denominator. 3/4 turns into 30/40. 2/5 turns into 16/40. 3/8 turns into 15/40. 7/10 turns into 28/40. 11/20 turns into 22/40. And 23/40 stays as it is, because the denominator is already 40.
Putting them in order is now simple,
3/8 (15/40) < 2/5 (16/40) < 11/20 (22/40) < 23/40 < 7/10 (28/40) < 3/4 (30/40)
***When you multiply any fraction to change its denominator, multiply it by the same thing to the numerator as well.
Good Luck!
If you show the menu I can help
the answer is b. 30 hope this helps
