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2 years ago

GUYS PLEASE HELPP PLSPLSOLSOAKGDJXG

Mathematics

1 answer:

ladessa [460]2 years ago

5 0

Answer:

Let S = starting point

Let ST = length of tunnel

SR = 1414 m

RT = 2236 m

Set up:

ST^2 + SR^2 = RT^2

ST^2 + (1414)^2 = (2236)

Solve for RT to find your answer.

Step-by-step explanation:

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Step-by-step explanation:

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$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

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$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

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This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

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$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

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GUYS PLEASE HELPP PLSPLSOLSOAKGDJXG​

GUYS PLEASE HELPP PLSPLSOLSOAKGDJXG