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zimovet [89]
3 years ago
13

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

if β < α. sin(3x − 27) = cos(5x + 5)
A) 14°
B) 15°
C) 75°
D) 76°
Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

A) 14°

Step-by-step explanation:

If α and β are the two angles other than 90° in a right triangle, then we have the relation between α and β as, α+β=90°.

Therefore, Sin α = Sin (90° -β) =Cos β.

So, we can write the reverse as if Sin α = Cosβ, then we have α + β =90°.

It is given that, Sin (3x-27) = Cos (5x+5).

Hence, we can write (3x-27) + (5x + 5) = 90

⇒ 8x = 90+27-5 =112

⇒ x = 14°

Therefore, option A. is correct. (Answer)

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Given independent events A and B such that P(A) = 0.3 and P (B) = 0.5, which of the following is a correct statement?
aev [14]

Answer:

(D) P(AUB) = 0.65

Step-by-step explanation:

Since A and B are independent:

P(A ^ B)

= P(A) × P(B)

= 0.3 × 0.5 = 0.15

P(AUB) = P(A) + P(B) - P(A^B)

= 0.3 + 0.5 - 0.15

= 0.65

7 0
3 years ago
What is the area of the figure down below
kogti [31]

68


Explanation:

So to get this answer you need to split it into smaller shapes. We already have the squares so we know that 3*3 is 9 and then we double that because there are two of them.

So, so far we have 18+x

We need to take the middle shape and split it into two trapezoids.

The area for trapezoids is T=(a+b/2)h

So T= (3+7/2)5
T= 5*5=25
And then we would double that because there are two of them so 50 and then fill it in for x
18+50= 68 is the area of the figure.
3 0
3 years ago
Which choices are equivalent to the fraction below? check all that apply 16/36
kenny6666 [7]

Answer:

\frac{16}{36} = \frac{8}{18} = \frac{4}{9}

Step-by-step explanation:

\frac{16}{36} = \frac{16/4.5}{36/4.5} = \frac{3.5555}{8} \neq  \frac{3}{8} \\\\\frac{16}{36} = \frac{16/12}{36/12} = \frac{1.3333}{3} \neq  \frac{1}{3} \\\\\frac{16}{36} = \frac{16/9}{36/9} = \frac{1.7777}{4} \neq  \frac{1}{4} \\\\\frac{16}{36} = \frac{16/4}{36/4} = \frac{4}{9} \\\\\frac{16}{36} = \frac{16/7.2}{36/7.2} = \frac{2,2222}{5} \neq  \frac{2}{5} \\\\\frac{16}{36} = \frac{16/2}{36/2} = \frac{8}{18} \\\\

3 0
3 years ago
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
Find the measure of CP
dmitriy555 [2]

Given:

A figure ABCP.

To find:

The measure of CP.

Solution:

In triangles ABP and CBP,

\angle PAB\cong \angle PCB            (Given right angles)

\angle ABP\cong \angle CBP            (Given)

BP=BP            (Common side)

Now,

\Delta ABP\cong \Delta CBP        (By AAS property of congruence)

We know that the corresponding parts of congruent triangles are congruent.

AP=CP

8=CP

Therefore, the measure of CP is 8 units.

6 0
3 years ago
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