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2 years ago

Write two solutions for the following equation 2x+3y=24.

Mathematics

2 answers:

SVETLANKA909090 [29]2 years ago

4 0

Answer: (12, 0) and (0, 8)

Step-by-step explanation:

This equation is in standard form. We can sub in a number for x to solve for y and vice versa.

Let's sub in 0 for x.

$2x+3y=24\\2(0)+3y=24\\3y=24\\\frac{3y}{3} =\frac{24}{3} \\y=8$

When x is 0 y is 8 giving us the coordinate (0, 8).

Now lets sub in 0 for y

$2x+3(0)=24\\2x=24\\\frac{2x}{2} =\frac{24}{2} \\x=12$

When y is 0 x is 12 giving us the coordinate (12, 0)

lozanna [386]2 years ago

3 0

Step-by-step explanation:

Begin by solving for y

3y = -2x + 24 divide by 3

y =-(2/3)x + 24

Choose x so that it is divisible by 3

Let x = 6 which 3 can divide into evenly

y = -(2/3)*6 + 24 3 into 6 is 2 so you are left with

y = - 2 * 2 + 24

y = - 4 +24

y = 20

By a similar mthed, let x = 15

y = -2/3 x + 24

y = -2/3 * 15 +24

y = -2 * 5 + 24

y = -10 + 24

y = 14

So your two solutions are

(6,20)

(15,14)

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Answer:

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A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

$x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i$

The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor $x^2+9$ :

First, multiply the constant in the polynomial by $i^2$ where $i^2$ is equal to -1.

$x^2+9i^2$

Since both terms are perfect squares, factor using the difference of squares formula

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zhenek [66]

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Graph the function by first finding its zeroes. <br> y = x3- 2x2 + x

CaHeK987 [17]

Answer:

The zeros of the function are;

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Step-by-step explanation:

The zeroes of the function simply imply that we find the values of x for which the corresponding value of y is 0.

We let y be 0 in the given equation;

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We factor out x since x appears in each term on the Left Hand Side;

x ( x^2 - 2x + 1) = 0

This implies that either;

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We can factorize the equation on the Left Hand Side by determining two numbers whose product is 1 and whose sum is -2. The two numbers by trial and error are found to be -1 and -1. We then replace the middle term by these two numbers;

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x = 0 and x = 1

The graph of the function is as shown in the attachment below;

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