To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
F1 = 6*cos(30) i + 6*sin(30) j = 5.20 i + 3 j
<span>F2 = 0 i + 5 j </span>
<span>R = F1 + F2 </span>
<span>Add the 'i's together (x direction) and the 'j's together (y direction) </span>
<span>R = (5.20 + 0) i + (3 + 5) j = 5.2 i + 8 j </span>
<span>Magnitude: </span>
<span>||R|| = </span>√<span>(5.2^2 + 8 ^2) = </span>√<span>91 = 9.54 </span>
<span>Direction: </span>
Θ<span> = atan ( Rj / Ri ) = atan( 8 / 5.2 ) = 57.0</span>⁰
Answer:
Yes, it's an arithmetic sequence.
Step-by-step explanation:
Each term in this sequence is 4 more than the previous term. Therefore we have an arithmetic sequence.
Answer:
m=7=2+1894+4b=4x4=16
Step-by-step explanation:
Answer:
21.98 to the nearest hundredth.
Step-by-step explanation:
Geometric mean of x and y is √(xy)
= √(21*23)
= 21.98.
