Step-by-step explanation:
∫ dt / (cos²(t) ⁹√(1 + tan(t)))
If u = 1 + tan(t), then du = sec²(t) dt.
∫ du / ⁹√u
∫ u^(-1/9) du
9/8 u^(8/9) + C
9/8 (1 + tan(t))^(8/9) + C
Answer: -9.999e+23
I don't know what you're up to.
C=11/35
You subtract 4/35 from both sides.
Just make the equation look like this y = mx + b
So 3x + y =10 would equal y = -3x + 10