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2 years ago

Max is making a new password, using 2, 4, 7 and 9. How many passwords could he make using each number only once in the password?

Mathematics

1 answer:

d1i1m1o1n [39]2 years ago

6 0

Answer:

im going to feel awful if this is wrong but i believeeee its 16-

Step-by-step explanation:

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A hospital did a ten-year study on patients who used its services. One thousand patients were randomly selected and followed ove

Ugo [173]

Answer:

Step-by-step explanation:

8 0

2 years ago

What represents the inverse of the function f(x)=4x

Yuki888 [10]

Answer:

$\frac{x}{4}$

Step-by-step explanation:

The given function is

f(x) = 4x

As we know

f(x) = y, which implies x= $f^{-1} (y)$

Therefore,

y = 4x

x = $\frac{y}{4}$

as x= $f^{-1} (y)$

So,

$f^{-1} (y) = \frac{y}{4}$

replacing y by x in the above expression

$f^{-1} (x) = \frac{x}{4}$

So our inverse function is $\frac{x}{4}$

4 0

2 years ago

2s+t=r solve for t rearrange the variables

DedPeter [7]

Answer:

Step-by-step explanation:

2s + t = r

t = r - 2s

8 0

1 year ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago

How to write 1000= in Exponential form

Nadusha1986 [10]

Answer:

10x^{3}[/tex]

Step-by-step explanation:

$10x^{3}$

=10·10·10

=1000

5 0

2 years ago

Read 2 more answers