2 years ago

What is the first step when applying properties of operations to divide 73.85 by 4.1?

Mathematics

1 answer:

Alchen [17]2 years ago

5 0

Answer:

B. Multiply the divisor and dividend by 100.

Step-by-step explanation:

Multiply by 100 to get rid of the decimal

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An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $6600 and his st

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Answer:

4.9%

Step-by-step explanation:

6600 * 107/100 = 66*107 = 7062.

3500 * 101/100 = 35x101 = 3535

7062+3535=10597. Original worth: 10100

10597-10100 = 497

497/10100 = 0.0492079208, or 4.92%, rounds to 4.9%

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1 year ago

Mrs.Young’s recipe for haggis calls for 2 1/4 cups of stock and serves 12. How much stock will she need to make 4 servings of ha

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3 1/4

Step-by-step explanation:

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3 years ago

Kate has 48 softballs. She wants to divide them evenly among b softball bags. Which expression represents how many softballs she

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Answer:

Softballs = (48/b)

Step-by-step explanation:

Given that,

Total number of softballs = 48

She wants to divide them evenly among b softball bags.

We need to find an expression that represents how many softballs she should put into each bag.

As it is dividing among b softball, it means we divide 48 and b. So,

$s=\dfrac{48}{b}$

Hence, the required expression is (48/b).

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2 years ago

Angle C is an inscribed angle of circle P. Angle C measure (17x-2) and arc AB measure (20x+10). Find X

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10x + 5 = 16x - 1
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3 years ago

Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.

Elden [556K]

Answer:

The answer is " $cirtical\ points \ (x,g(x))\equiv (e,0),(e+3,\frac{27}{e^3})$ "

Step-by-step explanation:

Given:

$g(x) = (x-e)^3e^{-(x-e)}$

Find critical points:

$g(x) = (x-e)^3e^{(e-x)}$

differentiate the value with respect of x:

$\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r} \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]$

critical points $g'(x)=0$

$\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3$

So,

The critical points of $(x,g(x))\equiv (e,0),(e+3,\frac{27}{e^3})$

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3 years ago