If John's car gets an average of 18 mpg and he fills his tank with 26.7 gallons of gas, how far can John travel on a tank of gas
2 answers:
Answer:
480.6 miles.
Step-by-step explanation:
We have been given that John's car gets an average of 18 mpg. John fills his tank with 26.7 gallons of gas.
To find the distance traveled by John's car, we will multiply the distance covered per gallon by number of gallons in the tank.
Therefore, John can travel 480.6 miles on a tank of gas.
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Answer:
a: 28 < µ < 34
Step-by-step explanation:
We need the mean, var, and standard deviation for the data set. See first attached photo for calculations for these...
We get a mean of 222/7 = 31.7143
and a sample standard deviation of: 4.3079
We can now construct our confidence interval. See the second attached photo for the construction steps.
They want a 90% confidence interval. Our sample size is 7, so since n < 30, we will use a t-score. Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)
The t-value is: 1.943
We rounded down to the nearest person in the interval because we don't want to over estimate. It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate. It's better to use 28 and underestimate a little when considering customer flow.
Answer:
- 16
Step-by-step explanation:
Average is calculated as
average =
Thus for the given 10 numbers we have
= - 5 ( multiply both sides by 10 )
total = - 50
let the number added be x, then
= - 6 ( multiply both sides by 11 )
total + x = - 66, that is
- 50 + x = - 66 ( add 50 to both sides )
x = - 16
The new number is - 16