A 16 mile race is made up of 3 equal sections. Which equation shows how to find the number of miles in each section?

If twelve pounds of nails cost $3.84 what is the unit cost A) 32c B) 28c C) 23c D) 18c

aalyn [17]

Answer:

Option A) 32c

Step-by-step explanation:

we know that

To find the unit cost, divide the total cost of twelve pounds by twelve pounds

so

$\frac{\$3.84}{12}=\$0.32$

Remember that

1$=100 cents

Convert dollars to cents

$\$0.32=0.32*100=32c$

therefore

The cost of one pound of nails cost 32 cents

7 0

3 years ago

Read 2 more answers

Please show step by step a)6 ÷2(1+2) b)48 ÷2(9+3) c)9-3 ÷⅓ +1

UNO [17]

Answer:

1

Step-by-step explanation:

a)2 times 1 and then times 2 become (2+4) then 6 ÷ 6 (because 2 plus 4)

7 0

3 years ago

What is the solution to the pair of simultaneous equations? 2x+y=5. 3x-2y=4

densk [106]

Answer:

(2, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Terms/Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

2x + y = 5

3x - 2y = 4

Step 2: Rewrite Systems

Manipulate 1st equation

[Subtraction Property of Equality] Subtract 2x on both sides: y = 5 - 2x

Step 3: Solve for x

Substitution

Substitute in y [2nd Equation]: 3x - 2(5 - 2x) = 4
[Distributive Property] Distribute -2: 3x - 10 + 4x = 4
[Addition] Combine like terms: 7x - 10 = 4
[Addition Property of Equality] Add 10 on both sides: 7x = 14
[Division Property of Equality] Divide 7 on both sides: x = 2

Step 4: Solve for y

Substitute in x [Modified 1st Equation]: y = 5 - 2(2)
Multiply: y = 5 - 4
Subtract: y = 1

3 0

3 years ago

8. Michael has $68. Craig has $24 less than Michael has. Michael spends $20 on a new hat. The solution

kaheart [24]

Ni idea de cual es la respuesta mi loco

4 0

2 years ago

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

LuckyWell [14K]

Answer:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

$df = n_1 +n_2 -2 = 10+15-2= 23$

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

$\bar X_1 = 1085$ sample mean for group 1

$\bar X_2 = 1034$ sample mean for group 2

$n_1 = 10$ sample size for group 1

$n_2 = 15$ sample size for group 2

$s_1 = 52$ sample deviation for group 1

$s_2 = 61$ sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: $\mu_1= \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

And the statistic is given by:

$t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}$

And replacing we got:

$t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 10+15-2= 23$

And the p value would be:

$p_v = 2*P(t_{23} >2.240) = 0.035$

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0

3 years ago