Let's go:
The centroid of a triangle is the point of intersection of its medians. The distance from de centroid to some vertex of triangle to which it belongs is equal to 2/3 of the length of its median:
BM = 18/3 = 6
I hope I helped you.
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
Answer:
-2
Step-by-step explanation:
From the position of 2 on the x axis, just trace down to the graph.
Where the trace intersects the graph, then trace this point to the y-axis
This gives -2
your answers are B. 25 and C -25
So the answer is c because I have done this before like a think a year ago
