Central angle = 360 / 24 = 15 degrees
ARc length = r * theta, where theta is the angle in radians and r = radius
= 15 * 15 * pi/180
= 3.93 feet to nearest hundredth.
Area of sector = area of circle / 24 = pi*15^2 / 24 = 29.45 ft^2
Answer:
p=-6
q=3
Step-by-step explanation:
5p-3q=-39
-2p-3q=3
Multiply the second equation by -1
2p +3q = -3
Add the first equation and the modified second equation
5p-3q=-39
2p +3q = -3
---------------------
7p = -42
Divide by 7
7p/7 = -42/7
p = -6
Now we can find q
2p +3q = -3
2(-6) +3q = -3
-12 +3q = -3
Add 12 to each side
-12+12 +3q = -3+12
3q = 9
Divide by 3
3q/3 = 9/3
q=3
You will need 28 rows because if you divide 224 by 8 you would get 28 (:
If the two lengths are 7 and 3, then I believe the length of the hypotenuse would be approximately 7.62.
Step-by-step explanation:
![\sin( \alpha ) = \frac{ \sqrt{5} }{3} \\ \alpha = 48.19 \: degrees \\ \cos( \alpha ) = \frac{2}{3}](https://tex.z-dn.net/?f=%20%5Csin%28%20%5Calpha%20%29%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B5%7D%20%7D%7B3%7D%20%20%5C%5C%20%20%5Calpha%20%20%3D%2048.19%20%5C%3A%20degrees%20%20%5C%5C%20%20%20%5Ccos%28%20%5Calpha%20%29%20%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20)