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2 years ago

5

10. Two plots of land, one square and other rectangle have same perimeter. If the rectangular field is of size 90 m by 70 m, whi

ch plot has greater area and by how much?

1 answer:

masya89 [10]2 years ago

7 0

Answer:

Here is your answer.

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Which two are equivalent?

never [62]

Answer:

Expression I and IV

Step-by-step explanation:

Expression I simplified :

3n + 7 + n + 4n
8n + 7
Expression I = Expression IV

7 0

2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

B) 90 minutes : 12 hours<br>3

skad [1K]

I don’t quite understand your question

3 0

2 years ago

What is the surface area of 6x1x8

Agata [3.3K]

48 because you multiply

5 0

2 years ago

Read 2 more answers

Solve the following system of equations by graphing. 3x - 2y = -6 - 3x - y = -12

MA_775_DIABLO [31]

9514 1404 393

Answer:

(x, y) = (2, 6)

Step-by-step explanation:

See the attachment for the graph.

4 0

2 years ago