Answer:
We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.
Step-by-step explanation:
For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive
The confidence level is given 95%, the significance level would be given by 
and 
. And the critical values are:
The estimated proportion of people satisfied with the quality of education the students receive is given by:
The confidence interval for the proportion if interest is given by the following formula:
And replacing the info given we got:
We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.
Answer: 34%.
By definition of normal distribution, ≈68% of the data is within 1 standard deviation of the mean. Therefore 68% of IQs are between 85 and 115, and half of that is on the lower end, 85 to 100.
Complementary angles add up to 90 degrees. We know that AXB is 20 degrees, and AXB is complementary to CYD and FZE. So CYD and FZE are 90-20, so each angle is 70 degrees
CYD = 70 degrees
FZE = 70 degrees
CYD + FZE = 70 + 70 = 140
Proofs are... well... just that. They are your proof for why a certain property works or what you did to show your work. So essentially, you just do math like normal, a proof is showing what you did and why it works.
1. Find the derivative of <span>P(x)=3x^3+2x^2-6x. It's P'(x)=9x^2 + 4x - 6.
2. Set this result equal to zero and solve for the critical values:
</span> 9x^2 + 4x - 6 = 0 Using the quadratic formula, I got
x = [-4 plus or minus sqrt(232)] / 18. Reducing this,
x = [-4 plus or minus 2 sqrt(58)]; thus, there are two real, unequal roots and two real, unequal critical values.
3. One at a time, examine the two critical values: determine whether the derivative changes from neg to pos or from pos to neg at each of these values. Example: If the derivative is pos to the left of the first c. v. and neg to the right, we've got a local max.
4. Since there are only 2 critical values, you can have no more than 1 local max (corresponding to a change in the sign of the derivative from pos to neg) and one local min. (from neg to pos).
Message me if this explanation is not sufficient to help you understand this problem thoroughly.
