F(x)=4(2)^x what would a graph of this look like?
1 answer:
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Answer:
see attached
Step-by-step explanation:
A graphing calculator can do a nice job of showing you what the graph looks like.
The initial factor of 4 is the value when x=0, the y-intercept. The base of 2 tells you the function value is multiplied by 2 for each unit of x to the right, and divided by 2 for each unit of x to the left. (The curve quickly goes off the top of the graph.)
The horizontal asymptote is y=0, as it is for all exponential functions (that have not been translated).
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Cross-multiplying and rearranging, we get:
or written without using latex:
k^2 = h^2 - 3mq
Can you finish now?