Answer:
Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion
Adding above two, we get
⇒
⇒
⇒
⇒
⇒
⇒
Answer:
8 (7.94)
Step-by-step explanation:
You can think of it as a geometry problem.
What is formed here is a triangle, which sides ate: the line, the line's shadow, and the height from the ground to the kite (here I attach a drawing).
What you need to find is the height. We will call it H.
As the triangle formed is a right one, we can use Pitágoras' theorem. The height H squared plus the squared of the shadow is equal to the squared of the line (the hypotenuse). This is:
H^2 + 9^2 = 12^2
H^2 + 81= 144
H^2 = 63
Applying squared root in both sides
H = √63
H = 7,94
So, the height is approximately 8.
