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Aliun [14]
4 years ago
6

You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftove

r piece is long enough, you will use it in another fixture . How long will the leftover piece be ? 23 and 7/8 1 and 51/70 7 and 1/8 6 3/8
Mathematics
1 answer:
Bumek [7]4 years ago
6 0

Answer:   6\dfrac{3}{8}\text{ inches}

Step-by-step explanation:

Given: Original length = 15\dfrac{1}{8} inches

=\dfrac{8\times15+1}{8}=\dfrac{121}{8} inches                      ( In improper fraction )

Length of piece cut from original = 8\dfrac{3}{4} inches

=\dfrac{4\times8+3}{4}= \dfrac{35}{4} inches                 ( In improper fraction )

Length of piece leftover piece =  (Original length ) - (Length of piece cut )

=\dfrac{121}{8}-\dfrac{35}{4}\\\\=\dfrac{121-2\times35}{8}\\\\=\dfrac{121-70}{8}\\\\=\dfrac{51}{8}\\\\=6\dfrac{3}{8}\text{ inches}

Hence, the leftover piece will be 6\dfrac{3}{8}\text{ inches}  long.

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