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Aliun [14]
3 years ago
6

You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftove

r piece is long enough, you will use it in another fixture . How long will the leftover piece be ? 23 and 7/8 1 and 51/70 7 and 1/8 6 3/8
Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:   6\dfrac{3}{8}\text{ inches}

Step-by-step explanation:

Given: Original length = 15\dfrac{1}{8} inches

=\dfrac{8\times15+1}{8}=\dfrac{121}{8} inches                      ( In improper fraction )

Length of piece cut from original = 8\dfrac{3}{4} inches

=\dfrac{4\times8+3}{4}= \dfrac{35}{4} inches                 ( In improper fraction )

Length of piece leftover piece =  (Original length ) - (Length of piece cut )

=\dfrac{121}{8}-\dfrac{35}{4}\\\\=\dfrac{121-2\times35}{8}\\\\=\dfrac{121-70}{8}\\\\=\dfrac{51}{8}\\\\=6\dfrac{3}{8}\text{ inches}

Hence, the leftover piece will be 6\dfrac{3}{8}\text{ inches}  long.

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ANSWER:

6_34/99

STEP:

So yes. When a decimal is repeating, you can take the repeating number (most likely a decimal) and put 99 under it. Since 99 cannot be solved, you put 99. So, 34/99. Though we are not finished. There is still the whole 6 number left. So, you do 6_34/99.

Proof:

10x=6.6...

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3 years ago
What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?
posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\

Since\  \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0

5 0
2 years ago
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Step-by-step explanation:

Write the given question as an equation and solve.

  80 km = 0.09 × (what distance)

  (80 km)/0.09 = what distance . . . . . divide by the coefficient of the variable

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80 km is 9% of 888.89 km

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JulijaS [17]

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Step-by-step explanation:

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