Question

Use long division to find the quotient. (x²+6x-27) ÷ (x-3)

Answer 1

$\frac{ x^2+6x-27 }{x-3} = \frac{ x^2+6x +3x-3x-27 }{x-3} = \frac{ x^2+9x-3x-27 }{x-3} = \\ \\ =\frac{ x(x +9 )-3(x+9) }{x-3} = \frac{ (x +9 ) (x-3) }{x-3} = x+9 \\ \\ \\ x-3\neq 0 \\x\neq 3\\D=R\setminus \left \{ 3 \right \}$