300 is the answer. Hope I helped :)
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
%P = 8%
the percentage of fat in the mixture is 8%
Step-by-step explanation:
Given;
The percentage of fat in the mixture is;
%P = total mass of fat in mixture/total mass of mixture × 100%
%P = F/T × 100% ….....1
Mass of fat in mixture is;
She purchases 5 pounds of ground beef which is 15% fat
F1 = 15% of 5 pounds = 0.15×5 pounds
F1 = 0.75 pound
and combines it with 7 pounds of ground turkey which is only 3% fat
F2 = 3% of 7 pounds = 0.03 × 7
F2 = 0.21 pound
Total mass F = F1 + F2
F = 0.75+0.21
F = 0.96 pound
Total mass of mixture T = 5 + 7 pounds
T = 12 pounds.
From equation 1,
%P = F/T × 100%
%P = 0.96/12 × 100%
%P = 0.08×100%
%P = 8%
the percentage of fat in the mixture is 8%
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The answer would be 8500m
