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faust18 [17]
3 years ago
12

A sequence has a common ratio of Three-halves and f(5) = 81. Which explicit formula represents the sequence?

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

f(n) = \frac{32}{3}(\frac{3}{2})^n

Step-by-step explanation:

Given

r = \frac{3}{2}

f(5) = 81

Required

The geometric sequence

A geometric sequence is represented as:

f(n) = ar^{n-1}

Replace n with 5

f(5) = ar^{5-1}

f(5) = ar^4

Substitute values for f(5) and r

81 = a* (\frac{3}{2})^4

Open bracket

81 = a* \frac{81}{16}

Make a the subject

a = \frac{81 * 16}{81}

a = 16

So, the explicit function is:

f(n) = ar^{n-1}

f(n) = 16 * (\frac{3}{2})^{n-1}

Split

f(n) = 16 * (\frac{3}{2})^n \div (\frac{3}{2})

Convert to multiplication

f(n) = 16 * (\frac{3}{2})^n * \frac{2}{3}

f(n) = \frac{32}{3}(\frac{3}{2})^n

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