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Radda [10]
4 years ago
13

Select all expressions that are equivalent to 16x − 12 − 24x + 4 by showing your work & explain your reasoning. 1)40x - 16 2

)4 - 12 - 4x + (- 4x) 3) 8x - 8 4)-8 (r + 1)
Mathematics
1 answer:
professor190 [17]4 years ago
5 0

Answer:

4 - 12 - 4x + (- 4x)

-8 (x + 1)

Step-by-step explanation:

16x - 12 - 24x + 4

16x - 24x - 12 + 4

-8x - 8

1)40x - 16 = not equivalent

2)4 - 12 - 4x + (- 4x)

4 - 12 - 4x - 4x

-8 - 8x = - 8x - 8 (equivalent)

3) 8x - 8 (not equivalent)

4)-8 (x + 1) = - 8x - 8 (equivalent)

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I need some help on area​
Hoochie [10]

Answer:

Step-by-step explanation:

If the lower right corner were present, the area would simply be

A = L * W

A = 16 * 8

A = 128

Since the lower right corner is not present, it's area is not there.

A = L * W

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6 0
4 years ago
Let y = (2 6) and u = (7 1). Write y as the sum of a vector in Span(u) and a vector orthogonal to .
Minchanka [31]

The question is missing. Here is the complete question.

Let y = \left[\begin{array}{ccc}2\\6\end{array}\right] and u = \left[\begin{array}{ccc}7\\1\end{array}\right]. Write y as the sum of a vector in Span(u) and a vector orthogonal to u.

Answer: y = \left[\begin{array}{ccc}\frac{21}{10} \\ \frac{3}{10} \end{array}\right] + \left[\begin{array}{ccc}\frac{-1}{10}\\ \frac{57}{10} \end{array}\right]

Step-by-step explanation: The sum of vectors is given by

y =  y_{1} + z

where  y_{1} is in Span(u);

vector z is orthogonal to it;

First you have to compute the orthogonal projection y_{1} of y:

y_{1} = proj y = \frac{y.u}{u.u}.u

Calculating orthogonal projection:

\left[\begin{array}{c}2\\6\end{array}\right].\left[\begin{array}{c}7\\1\end{array}\right] = \left[\begin{array}{c}9\\6\end{array}\right]

\left[\begin{array}{c}7\\1\end{array}\right].\left[\begin{array}{c}7\\1\end{array}\right] = \left[\begin{array}{c}49\\1\end{array}\right]

y_{1} = \frac{9+6}{49+1}.u

y_{1} = \frac{15}{50}.u

y_{1} = \frac{3}{10}.u

y_{1} = \frac{3}{10}.\left[\begin{array}{c}7\\1\end{array}\right]

y_{1} = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]

Calculating vector z:

z = y - y_{1}

z = \left[\begin{array}{c}2\\6\end{array}\right] - \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]

z = \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]

Writing y as the sum:

y = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right] + \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]

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3 years ago
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Bas_tet [7]

Answer:

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Step-by-step explanation:

The computation of the original amount is shown below:

As we know that

Future value = Present value × (1 + rate of interest)^number of years

So,

Present value = Future value ÷ (1 + rate of interest)^number of years

= $3,024.56 ÷ (1 + 0.26 ÷ 2)^5

= $1,642

Hence, the original amount is $1,642

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3 years ago
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zalisa [80]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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