3 years ago

Find the value of of x sin(4x+30)°=cos(-2x+54)°

Mathematics

1 answer:

user100 [1]3 years ago

6 0

Answer:

fhxhfbccbbn

cfhjhkj

ffuhhoh

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Here’s a polygon:

kozerog [31]

Answer

IJKL & EFGH

<h3>Step-by-step explanation:</h3><h3>IJKL & EFGH are similar because they are the same.</h3>

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3 years ago

Priya has a recipe for banana bread. She uses 7 1/2 cups of flour to make 3 loaves of banana bread. Andre will follow the same r

DochEvi [55]

9514 1404 393

Answer:

A. b = 2/5f

Step-by-step explanation:

Andre's equation is in the form ...

b = kf

The value of k can be found by dividing by f:

b/f = k

For Priya's recipe, the values are ...

b/f = k = 3/7.5 = 2/5

Andre's equation is ...

$\boxed{b=\dfrac{2}{5}f}$

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3 years ago

The simplified expression

Romashka-Z-Leto [24]

Answer:

$5x^2 y^2$

Step-by-step explanation:

We need to use the properties shown below to solve this:

1. $\sqrt[n]{x^a} =x^{\frac{a}{n}}$

2. $\sqrt{x}\sqrt{x} =x$

3. $\sqrt{x} \sqrt{y}=\sqrt{x*y}$

Area of a triangle is given by 1/2 * base * height, so we do that and simplify:

$A=\frac{1}{2}(\sqrt{5x^3} )(2\sqrt{5xy^4} )\\A=\frac{1}{2}(5x^3)^{\frac{1}{2}}*2*(5xy^4)^{\frac{1}{2}}\\A=\sqrt{5}x^{\frac{3}{2}}*\sqrt{5}\sqrt{x} } y^2\\A=\sqrt{5} \sqrt{5}x^{\frac{3}{2}} x^{\frac{1}{2}}y^2\\A=5*x^2y^2\\A=5x^2 y^2$

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3 years ago

Choose a point on the terminal side of theta theta= 5pi/4

adell [148]

Answer:

Step-by-step explanation:

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3 years ago

One of the parking lot lights at a hospital has a motion detector on it, and the equation (x+10)2+(y−8)2=16 describes the bounda

DIA [1.3K]

The correct answer is 4ft

<span>because the radius of that circle </span>
<span>(x+10<span>)^2</span>+(y−8<span>)^2</span>=<span>4^2</span></span>
<span>is 4</span>

5 0

3 years ago

Read 2 more answers