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Alisiya [41]
3 years ago
11

7th-grade work - Eric had a 25% discount on lacrosse equipment. The selling price was $127.50. What was the original price?

Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer:

$170 was the original price.

Step-by-step explanation:

$42.5 is 25% of $170, and $170-$42.5 is $127.5

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Find the length of side x in simplest radical form with a rational denominator.60°130°X
iren [92.7K]

We will solve using the law of sines as follows:

\frac{1}{\sin(30)}=\frac{X}{\sin (60)}

Now, we solve for X:

\Rightarrow X=\frac{\sin(60)}{\sin(30)}\Rightarrow X=\sqrt[]{3}

So, the length of X is sqrt(3).

5 0
1 year ago
The height of a model rocket is 4% of the height of the actual rocket. The model is 1.8 m high. How high is the actual rocket? (
Over [174]
4% = 1.8m
1% = 0.45m
100% = 0.45 x 100 = 45m
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Fiona doubled the original amount in her savings account, s. Which expression represents her new balance and what is that new ba
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Step-by-step explanation:

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3 years ago
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Pls help me very urgently needed
Kisachek [45]
Ratio is 7:9
add the ratio it becomes 16
272 members divided by 16
that makes it 17 per one ratio
women ratio is 9
17x9 is 153
i=153 women in the sports club

same thing with ii except it’s divided by 7
91/7 is 13
which means 13 per ratio
there are 9 ratios of women
9x13=117
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4 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

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3 years ago
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