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const2013 [10]
3 years ago
14

Which is the product of 4/5 x3/7

Mathematics
2 answers:
Keith_Richards [23]3 years ago
3 0

Answer:

12/35

Step-by-step explanation:

eimsori [14]3 years ago
3 0

Answer:

so I think it is 0.34

Step-by-step explanation:

4/5x3/7=0.34

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A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The
zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200,  300

Let X be the total refund payment on the seven day cruise.

We can say  X = 0, if there is no rain on all 7 days.

P(X = 0) = _nC_x * P^x * (1 - P)n-x

P(X = 0) =  _7C_o * 0.2^0 * (1-0.2)^{7-0

P(X = 0) =1 * 1* (1-0.2)^{7

P(X = 0) =(0.8)^{7

P(X = 0) =0.2097152

If it rains on any one day; then X = 100

P(X = 100) = _nC_x * P^x * (1 - P)n-x

P(X = 100) =  _7C_1 * 0.2^1 * (1-0.2)^{7-1

P(X = 0) =7 * 0.2* (1-0.2)^{6

P(X = 100) =7* 0.2* (0.8)^{6

P(X = 100) =0.3670016

if it rains on any two day  ; then X = 200

P(X = 200) = _nC_x * P^x * (1 - P)n-x

P(X = 200) =  _7C_2 * 0.2^2 * (1-0.2)^{7-2

P(X = 200) =  21 * 0.2^2 * (0.8)^{5

P(X = 200) = 0.2752512

if it rains on any three day or more than that ; then X = 300

P(X \ge 300) = 1 - P(X < 300)  \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple[Var X] =E [X^2] - (E [X])^2

where;

E[X^2]  = \sum x^2 \times p \\ \\ E[X^2]  = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\  E[X^2]  = 0  + 3670.016 + 11010.048+ 13322.88  \\ \\  E[X^2]  =28002.944

(E [X]) = \sum x * p\\ \\  (E [X]) =  0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0
3 years ago
6(x-4)=7(x+3) <br> Show your work
sergeinik [125]

Answer:

do distributive property on both, so multiply 6•x and 6•-4. then multiply 7•x and 7•3.

so it'll basically be 6x - 24 = 7x + 21.

then add 24 to both sides so: 6x - 24 + 24 = 7x + 21 + 24. since -24+24=0 it'll be 6x = 7x + 21 + 24.

then add 21 + 24 and that will be 45.

so 6x = 7x + 45

then subtract 7x from both sides 6x - 7x = 7x + 45 - 7x

that'll be -x = 7x + 45 - 7x

combine like terms (7x - 7x) = 0

so -x = 45

and since x can't be negative, do the opposite signs

so instead of -x = 45, make it x = -45

Hope it helped! (sorry that's its very long just wanted to show u the steps just in case)

3 0
3 years ago
Select the ordered pairs that are on the x-axis. Choose all that apply.
ZanzabumX [31]
-4,0 
2,0
both are true because they do not have a y coordinate, meaning they dont move off of the x-axis
6 0
3 years ago
Read 2 more answers
How do you round 38.25
solniwko [45]
Because its under 6 you must round it down to 38.20 if it was 38.68 for example it would be 38.70
4 0
3 years ago
Read 2 more answers
Question 13
natali 33 [55]

Answer:

y - 7 = (x + 5)

Step-by-step explanation:

Point-slope form: y - y1 = m(x - x1)

Slope(m) = 1

Point: (-5, 7) = (x1, y1)

To write the equation in point-slope form, we need to know the slope and one point. Since we were already given the values of the slope and one point, all we have to do is input those values into the equation:

y - y1 = m(x - x1)

y - 7 = 1(x - (-5))

y - 7 = (x + 5)

The equation in point-slope form is: y - 7 = (x + 5)

7 0
3 years ago
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