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3 years ago

Ivana got 21/25 on her science test. She got 86% on her math test. Which of her test marks is better? Explain.

Mathematics

1 answer:

mojhsa [17]3 years ago

7 0

Her math test is better.
if you take 21/25 you get 84%
86% > 84%

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viva [34]

Answer: Congruent

Step-by-step explanation:

Line BC is reflexive to itself

AB is congruent to CD, and that's given

Line AC is congruent to BC, using these prior proofs

Angle EDC and Angle FAB are congruent, and that's a given.

You can conclude that they are congruent by AAS

5 0

3 years ago

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

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and again to get back a result in terms of $t$ .

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3 0

3 years ago

iogann1982 [59]

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3 years ago

An automobile traveling at the rate of 30 ft/sec is approaching an intersection. When the automobile is 120 feet from the inters

Trava [24]

Answer:

Distance between automobile and the truck is 100 feet.

Step-by-step explanation:

Speed of the automobile towards the intersection = 30 ft per sec

Speed of the truck that crosses the intersection = 40 ft per sec.

Automobile is 120 feet apart when the truck passes through the intersection.

After 2 seconds distance traveled by the automobile = Speed × time

= 30 × 2

= 60 feet

So the distance of the automobile from the intersection = 120 - 60

= 60 feet

Distance traveled by truck in 2 seconds = 40 × 2

= 80 feet

Now distance between them can be calculated by Pythagoras theorem

Distance = $\sqrt{(60)^{2}+(80)^{2}}$

= $\sqrt{3600+6400}$

= $\sqrt{10000}$

= 100 feet

Therefore, after 2 seconds distance between the truck and the automobile will be 100 feet.

4 0

3 years ago

Four times y to the fourth power

Oksana_A [137]

As expression it will look like (4y)^4 which is same as 256y^4.

6 0

3 years ago