Distance between T(80, 20) and U(20, 60) = sqrt((20 - 80)^2 + (60 - 20)^2) = sqrt((-60)^2 + (40)^2) = sqrt(3600 + 1600) = sqrt(5200) = 72.11 units
Distance between T(80, 20) and V(110, 85) = sqrt((110 - 80)^2 + (85 - 20)^2) = sqrt((30)^2 + (65)^2) = sqrt(900 + 4225) = sqrt(5125) = 71.59
Distance between U(20, 60) and V(110, 85) = sqrt((110 - 20)^2 + (85 - 60)^2) = sqrt((90)^2 + (25)^2) = sqrt(8100 + 625) = sqrt(8725) = 93.41
Therefore, shortest distance for the trip = 71.59 + 93.41 = 165 units.
Hi, thank you for posting your question here at Brainly.
Since the hedge is surrounding the square base, the area of the base can be determined by subtracting the area of the base from the hedge.
A = pi*r^2 - (4x)^2
A = pi*(6x)^2 - (4x)^2
A = 2x^2*(3pi - 2)
I hope I was able to answer your question. Have a good day.
Answer:
-4n^4-4n^2-8n+3
Step-by-step explanation:
you combine the like terms
The answer is 127.16 pi m³, hope this helps.
Answer:
Q 12 roots of the equation
∝ =
β =
no matter if u oppose the root
(i) 2()+2()+2(
(ii)( - 3 ()() + () =
Q 13 roots of equation
the roots of the second equation are
x1 = 1/3(-0.693) = -0.231
x2 = 1/3(1.443) = 0.481
the equation is
(x+0.231)(x-0.481)=0