Answer:
encerio y eso
Step-by-step explanation:
7/12-9/8(2x-1)-5/6(3x+2)=0
(7*2-9(2x-1)*3-5(3x+2)*4)/24=0
(14-9(2x-1)*3-5(3x+2)*4)/24=0
(14-27(2x-1)-20(3x+2)/24=0
(14-54x+27-60x-40)/24=0
(14+(-54x-60x)+27-40)/24=0
(14-114x+27-40)/24
(-144x+1)/24=0
-114x+1=0
-114x=-1
x=1/144
Answer:
A) 25
B) 64
Step-by-step explanation:
Hope this helps :))
Mulitpilicty is how many times a root repeats
factor
factor x first
x(2x^2+x-1)
using math
(x)(x+1)(2x-1)
no roots repeat
if it is equal to 0 then the roots are
0 multiplicty 1
-1 multiplicty 1
1/2 multiplicty 1
Answer:
90, 91 and 92
Step-by-step explanation:
Given
Consecutive integers = 273
Required
Find the integers
The question seem to be incomplete. However, I'll assume we're dealing with sum.
Let the smallest integer be y.
So,
y + y + 1 + y + 2 = 273
Collect like terms.
y + y + y = 273 - 2 - 1
3y = 270
Divide both sides by 3
y = 90
Hence, the integers are 90, 91 and 92
