3 years ago

Can somebody help with geometry? I need to know how to prove it to be a rectangle. I already proved parallelogram.

1 answer:

8 0

I'm not sure how to give you solid proof, like an equation or something, but you can see that out of the four coordinates, two of them have the y-value of 4 and two of them have the y-value of 2. Also, there is 1.5 in between each x-value that is paired with the same y-value... if that makes sense. So for (0.5, 2) and (3, 2), there is 1.5 in between 0.5 and 3. I hope this helps! Sorry it's a bit of a weird answer

You might be interested in

Triangle A’B’C is the image ABC under a translation.

grigory [225]

A translation by 3 units to the right.

6 0

2 years ago

I WILL MARK AS BRAINLIEST!!! What is the value of x?<br><br> 8x+3=43

uysha [10]

8x+3=43
-3 -3
8x=40
/8 /8
X=5

8 0

2 years ago

Daniel has lunch at a restaurant and the cost of his meal is $49.00, because of the service, he wants to leave a 5% tip. what is

yuradex [85]

49*1.05= $51.45

Hope it helped

8 0

3 years ago

Graphing Linear Equations

ArbitrLikvidat [17]

Answer:

Kyra=15 points

Liam=20 points

30 points=y=4/3x+5

Step-by-step explanation:

I graphed each equation and point on the graph given

HOPE THIS HELPS!!! :)

PLEASE CORRECT ME IF IM WRONG

8 0

3 years ago

Which set of rectangular coordinates describes the same location as the polar coordinates (6sqrt 2, 3pi/4)

Sonja [21]

Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?

x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6

y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6

Rectangular coordinates of the point = (x,y) =(-6,6)

Answer: Option a. (-6,6) </span>

8 0

2 years ago