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julsineya [31]
4 years ago
12

Simplify negative 7 and 1 over 8 − negative 9 and 1 over 2.

Mathematics
1 answer:
bulgar [2K]4 years ago
5 0

Answer:

answer is D : 2 3/8

Step-by-step explanation:

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Using the Distance Formula and the Pythagorean Theorem, find the distance, to the nearest tenth, from F
Fantom [35]

Answer:

<h2>        d = 8.9</h2>

Step-by-step explanation:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\(3,2)\quad\implies\quad x_1=3\,,\ \ y_1=2\\\\(-5,-2)\quad\implies\quad x_2=-5\,,\ \ y_2=-2\\\\d=\sqrt{(3+5)^2+(2+2)^2}=\sqrt{8^2+4^2}=\sqrt{64+16}=\sqrt{80}\approx8.9

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3 years ago
How can you find the value of n in this equation?
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4 0
3 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

3 0
3 years ago
Read 2 more answers
The value of the digit 5 in 24,513 is how many times the value of the 5 in 357?
olchik [2.2K]
24,513 500
357 50
500/50 = 10
10 times greater
4 0
3 years ago
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