Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
The system of equations 2x + 3y = 2 and y = (1/2)x + 3 have solutions at x = -2 and y = 2
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
From the system of equations 2x + 3y = 2 and y = (1/2)x + 3, the graph of the equation shows that the solution is at x = -2 and y = 2
Find out more on equation at: brainly.com/question/2972832
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Answer:
Reason:
1) assumptions given
2) RUTS is a rectangle
3) RUTS is a rectangle
4) because:
+) ∠STU and ∠SRU are the right angles
+) RU = ST; UT = RS
=> ΔURS ≅ ΔSTU (SAS)
5) because ΔURS ≅ ΔSTU (SAS) => ∠USR = ∠SUT
Step-by-step explanation:
We will not know the answer because you didn't tell us the radius or anything
Answer:
what do you need help wth ?
Step-by-step explanation:
