Answer:
1256 cubic yards of sand.
Step-by-step explanation:
In this question we have to find the volume of cone formed by sand.
Height of the cone is = 36 feet
Radius of the cone = 60/2 =30 feet.
Now we know the formula of volume of cone v = π r² (h/3)
By putting the values of r and h we can get the volume of sand to spread.
Volume = π×(30)²×(36/3) = 3.14×900×12 feet³
= 33912 feet³
Now we will convert feet³ to cubic yards
Since 1 cubic feet = .037037 cubic yards
therefore 33912 cubic feet = 33912×.037 = 1256 cubic yards.
So the answer is 1256 cubic yards of sand has the department received.
I don't see a square root sign anywhere, so I'll assume the integral is

First complete the square:

Now in the integral, substitute

so that

Under this change of variables, we have

so that

Under the right conditions, namely that cos(<em>t</em>) > 0, we can further reduce the integrand to


Expand the sine term as

Then


So the integral is

The value of x+y+z = 93
<u>Explanation:</u>
<u></u>
angle 1 = 18x
angle 2 = x+y
angle 3 = 30z
In rhombus, the diagonals intersect at 90°
Therefore,
angle 1 : 18x = 90
x = 90/18 = 5
angle 2: x+y = 90
5+y = 90
y = 85
angle 3: 30z = 90
z = 90/30 = 3
Value of x+y+z = 5+85+3 = 93
Thus, the value of x+y+z = 93
Answer: Number of College Faculty The number of faculty listed for a variety of private colleges which offer only bachelor’s degrees is listed below. Use these data to construct a frequency distribution with 7 classes, a histogram, a frequency polygon, and an ogive. Discuss the shape of this distribution. What proportion of schools have 180 or more faculty? 165 221 218 206 138 135 224 204 70 210 207 154 155 82 120 116 176 162 225 214 93 389 77 135 221 161 128 310 Source