Answer:
Katherine need to work minimum 10 hours lifeguarding to meet her requirements
Step-by-step explanation:
Given:
Rate for Lifeguarding = 
Rate for walking dogs = 
She had worked 2 hours walking dog
Money for walking dogs = Rate for walking dogs
hours worked=
she can work a maximum of 15 total hours and must earn at least $160.
Let hours required for lifeguarding be x
Money for life guarding = Rate for walking dogs hours worked for lifrguarding= 
Total Money she must earn = Money for lifeguarding + Money for walking dogs
Rounding to nearest hour
Katherine need to work minimum 10 hours lifeguarding to meet her requirements
Slope point form:
We need the slope "m" and a point (x₀,y₀)
y-y₀=m(x-x₀)
1)
we calculate the slope "m".
Given two points:
(x₁,y₁)
(x₂,y₂)
the slope "m" is:
m=(y₂-y₁) / (x₂-x₁)
In this case:
(4,10)
(6,11)
m=(11-10) / (6-4)=1/2
Now, we calculate the solpe point form.
(4,10)
m=1/2
y-y₀=m(x-x₀)
y-10=(1/2)(x-4)
we make the standard form
y-10=x/2 - 2
Lowest common multiple=2
2y-20=x-4
-x+2y=-4+20
-x+2y=16
Answer: -x+2y=16
3x-5 is a midline of that triangle so:
Answer D.
Answer:
rounded to the nearest ten thousand
2,034,627
2,030,000
Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
