<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
112
/ \
2 56
/ \
2 28
/ \
2 14
/ \
2 7
So, the answer is 2 x 2 x 2 x 7 or 2^3 x 7
The entire yard is 36x54 so you would draw a rectangle with those measurements, since there is a border of 3 you should draw another rectangle in the middle with measurements 6 less than the original. 30x48
since you are finding the area of the walk, you would find the larger area, then subtract the smaller rectangle
(36*54)-(30*48)
1944-1440
504 square feet of walk
Divide top and bottom by any number that's fits into both of them keep doing that until it's not possible Hope that helped Have a good day! :-)
Answer: 
Step-by-step explanation:
Given
The area of the base is 
height of the triangular prism is 
The volume of a triangular prism is 
The volume of given Prism is
The volume of the triangular prism is
