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4 years ago

2/5y-4+7-9/10y simplify

Mathematics

2 answers:

Vaselesa [24]4 years ago

6 0

- y - 6
------------
2

GenaCL600 [577]4 years ago

6 0

Answer:

-1/2y + 3

Step by step:

2/5y−4+7−9/10y

=2/5y+−4+7+−9/10y

Combine Like Terms:

=2/5y+−4+7+−9/10y

=(2/5y+−9/10y)+(−4+7)

=−1/2y+3

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winnie wrote the following riddle i am a number between 60 and 100 my ones digit is two less than my tens digits im a prime numb

Lina20 [59]

<span>The answer is that 79 IS NOT correct because the riddle says "my ones digit is 2 LESS than my tens digit.." and 79 has 7 in tens and 9 in ones which means the ones digit is 2 MORE than the tens digit.

To solve
x has to be more than 60 and less than 100
the primes between those are 61,67,71,73,79,83, 89, 97
97 is two less in the ones than in the tens so it completes all of the requirements of the riddles therefore, 97 is the answer.</span>

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4 years ago

Read 2 more answers

A circle with a diameter of 25 inches

Oksana_A [137]

A =πr2

Π = 3.14

r = ½diameter = 25/2 =12.5 inches

∴ Area = 3.14 × 12.5 × 12.5 square inches

Area = 490.625 square inches

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3 years ago

The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 mi

lara [203]

Answer:

a) 33.33%)

b) 135 minutes

c) 8.66 min

d) 50%

Step-by-step explanation:

a) the probability for a uniform distribution is

P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values

therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)

P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)

b) the mean (expected value) for a uniform probability distribution is

E(X) = (c+d)/2 = (120+150)/2 = 135 minutes

c) the standard deviation for a uniform probability distribution is

σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²

σ = √75 min² = 8.66 min

b) following the same procedure as in a)

P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)

4 0

3 years ago

if the force acting on an object stays the same, then the acceleration of the object is inversely proportional to its mass. if a

kykrilka [37]

6 = k/9 => k = 6 x 9 = 54 N

a = 54/2 = 27 meters per second per second

6 0

3 years ago

If the filling equipment is functioning properly what is the probability that the volume of oil in a randomly selected barrel wi

Sophie [7]

Answer:

$P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)$

$P(Z>0.8)=1-P(Z\leq 0.8)$

$P(Z>0.8)=1-0.788=0.212$

Step-by-step explanation:

Assuming this previous info : "Trucks carry barrels of crude oil from a port in Texas to a distributer in New Mexico on long trailers. Filling equipment is used to fill the barrels with the oil. When functioning properly, the actual volume of oil loaded into each barrel by the filling equipment at the port is approximately normally distributed with a mean of 55 gallons and a standard deviation of 0.5 gallons. If the mean is greater than 55.4 gallons, the filling mechanism is overfilling."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the amount filling of a population, and for this case we know the distribution for X is given by:

$X \sim N(55,0.5)$

Where $\mu=55$ and $\sigma=0.5$

We are interested on this probability

$P(X>55.4)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)$

And we can find this probability using the complement rule:

$P(Z>0.8)=1-P(Z\leq 0.8)$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(Z>0.8)=1-0.788=0.212$

8 0

3 years ago