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Naya [18.7K]
3 years ago
13

No need for explaining just direct answers plz

Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

the first 2

Step-by-step explanation:

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Midpoints <br> B is the midpoint of AC , find x.
PolarNik [594]

B is the midpoint which means both sides are equal to each other:

5x = 3x + 4

Subtract 3x from both sides

2x = 4

Divide both sides by 2

X = 2

4 0
3 years ago
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Which of the following best describes rotational symmetry
Gala2k [10]

Answer: B

Step-by-step explanation:

A best describes the quality of symmetry, not specifically rotational symmetry.

C applies to that of A.

D applies to flipping an image across an axis.

B specifically outlines the symmetry of an object when rotated, thus B would be the most precise answer.

7 0
3 years ago
WRITE AN EQUATION FOR EACH OF THESE AND SOLVE IT TO FIND THE VALUE OF THE UNKNOWN NUMBER:
castortr0y [4]

a) a *5+5= 20

5a + 5 = 20

5a = 20 - 5

5a = 15

a = 15/5

a = 3

b) b/5 - 5 = 4

b/5 = 4 + 5

b/5 = 9

b =9*5

b = 45

8 0
3 years ago
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In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
Please help me <br>by the way this is a 2 mark question from mathswatch​
BigorU [14]

Answer:

y = - 13, y = 13

Step-by-step explanation:

Given

y² = 169 ( take the square root of both sides )

y = ± \sqrt{169} = ± 13

Since 13 × 13 = 169 and - 13 × - 13 = 169

3 0
3 years ago
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