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Sonja [21]
3 years ago
14

PLLLSSSSS ANSWER THIS 40 POINTS

Mathematics
1 answer:
igomit [66]3 years ago
7 0
0.03125 beciase there are 32 people and one ticket make that as a fraction which is 1/32 and make it a decimal
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B17%7D%20%20%5Cdiv%20%20%5Cfrac%7B7%7D%7B10%7D%20" id="TexFormula1" title=
Lilit [14]

Your answer is 110/119

11/17 Divided By 7/10

11 * 10

17 * 7

110/119

That number can't be simplified, so that is your final answer.

Best of luck,

    - Ari -

8 0
3 years ago
Read 2 more answers
What is the perpendicular slope to the line y = 3/2+2?
Roman55 [17]

Answer:

slope is -2/3

Step-by-step explanation:

8 0
3 years ago
Lilia scores 15 points fewer than Bob, who scores 35 points. Carol scores half as many points as Lilia. How many points does Car
nignag [31]

Answer:

10  points the explantion is below

Step-by-step explanation:

Bob scored 35 points and Lilla scores 15 less so you start with 35 - 15. Then you want to divide 20 by 2 because Carol scored half as much as Lilla. Your equation is ( 35-15) / 2 = 10

3 0
3 years ago
Quiz 2 Problem A big ship drops its anchor. The variable ll l l models the anchor's elevation (in meters) relative to the water'
alexandr1967 [171]

Answer:

Initial height of the anchor is 75 meters.          

Step-by-step explanation:

We are given the following in the question:

l(t)=-2.4t+75

where, I is the anchor's elevation in meter after t seconds dropped from the ship.

We have to find the initial height of anchor that is we have to put t = 0  in the equation.

Putting t = 0, we get,

l(0)=-2.4(0)+75 = 75

Thus, initial height of the anchor is 75 meters.

3 0
3 years ago
Read 2 more answers
A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than
aleksklad [387]

Answer:

 The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  13

    The sample mean is  \= x =  9.63

     The standard deviation is  s =  0.585

      The significance level is  \alpha  =  0.05

The Null Hypothesis is  H_o :  \mu = 0

The Alternative  Hypothesis  is  H_a =  \mu < 10

The test statistic is  mathematically represented as

          t =  \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }

Substituting values

          t =  \frac{9.63  - 10 }{\frac{0.585}{\sqrt{13} } }

         t =  -  2.280

Now the critical value for \alpha is  

     t_{\alpha } = 1.645

This obtained from the critical value table

  So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

 The conclusion is that the researcher was correct

 

 

6 0
3 years ago
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