Given that quadrilateral QRST is a square.
Each angle of a square is of 90 degrees.
Angle <RQT is also an angle of 90 degrees.
We also given angle RQT = 3x - 6.
So, we can setup an equation as 3x-6 =90.
Now, we need to solve the equation for x.
6 is being subtracted from left side.
We always apply reverse operation. Reverse operation of subtraction is addition.
So, adding 6 on both sides of the equation, we get
3x-6+6 =90+6.
3x = 96.
3 is being multipied with x, in order to remove that 3, we need to apply reverse operation of multiplication.
So, dividing both sides by 3.
x=32 (final answer).
Answer:
y=x+10
Step-by-step explanation:
1.) y-1=1(x+9)
2.) y-1=x+9
3.) y=x+10
Answer:
1. 8x2 - 7x + 4x3 - 2-3x2 + 9x - 4 = 16+2x
Step-by-step explanation:
1. Multiply all the multiplication problems (should look like this --> 16-7x+12-2-6+9x-4)
2. Calculate the sum or difference (should end up looking like this --> 16-7x+9x) and then into this (16 +2x)
Bringing us to the answer → <u>16 + 2x!</u>
<u></u>
Answer:
12, 8, and 4
Step-by-step explanation:
a + d + a + a - d = 24
3a = 24 ⇒ [ a = 8 ]
and (a + d)² + a² + (a - d)² = 224
3a² + 2d² = 224
2d² = 224 - 192 = 32
d² = 16
[ d = ±4 ]
∴ The first three terms to A.P are
a + d = 8 + 4 = 12
a - = 8
a - d = 8 - 4 = 4
∴ Three terms are 12 , 8, and 4
You could interpret them as system of equation and answer the question easily
from A
-4x + y + x + w =1
write in same form from A
as this system has five variables and four of them are unknowns it means the unique solution is not possible
So, det (A) = 0
