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Dvinal [7]
3 years ago
14

Find all real numbers x that satisfy the equation (x-4)(x-8) = 12.

Mathematics
1 answer:
denis-greek [22]3 years ago
7 0

Answer:

x=10

Step-by-step explanation:

(10-4)(10-8) = 12

(6)(2) =12

12 = 12

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Answer:

a_{n} = 32(\frac{1}{4})^{n-1}

Step-by-step explanation:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

This means that for example:

a_{3} = a_{1}r^{3-1}

So

a_{3} = a_{1}r^{2}

2 = a_{1}(\frac{1}{4})^{2}

2 = \frac{a_{1}}{16}

a_{1} = 32

Then

a_{n} = 32(\frac{1}{4})^{n-1}

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Answer:

720

Step-by-step explanation:

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