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Dvinal [7]
2 years ago
14

Find all real numbers x that satisfy the equation (x-4)(x-8) = 12.

Mathematics
1 answer:
denis-greek [22]2 years ago
7 0

Answer:

x=10

Step-by-step explanation:

(10-4)(10-8) = 12

(6)(2) =12

12 = 12

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Answer:

The given set of equation are:   x+ (-45) ≤  35  ,  x - (-45) ≥  35

For the given equality to be true, x  ≤ 35

Step-by-step explanation:

Here, given the first number = x

Second number  = -45

Now, Sum of x  and - 45 is at most 35.

⇒ x+ (-45) ≤  35

Also,  The difference of x and -45 is at least 35.

⇒ x - (-45) ≥  35

Now, simplifying the given set of equations:

x  - 45  ≤  35  ⇒    -x - (-45) >   - 35   ( as 3  <  4  ⇒ -3  > -4)

or, -x  + 45  >  - 35

and second equation is x  + 45 ≥  35

Now, solving both the equations by not taking sign of inequality in to the consideration, we get

x - 45  = 35

x + 45 = 35  

Adding both equations,we get:   ⇒ 2x = 70

                                                          or x = 35

Hence for the given equality to be true, x  ≤ 35

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How do i solve 7 - n = 27
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