Answer:
![P(z](https://tex.z-dn.net/?f=%20P%28z%3C1.13%29%20%3D%200.8708)
And the best option would be:
![0.8708](https://tex.z-dn.net/?f=%200.8708)
Step-by-step explanation:
We assume that the distribution for the random variable is:
![X \sim N (\mu=0 , \sigma=1)](https://tex.z-dn.net/?f=%20X%20%5Csim%20N%20%28%5Cmu%3D0%20%2C%20%5Csigma%3D1%29%20)
For this case we want to calculate the following probability:
![P(z](https://tex.z-dn.net/?f=%20P%28z%3C1.13%29)
And we can use the normal standard distribution or excel and we got:
![P(z](https://tex.z-dn.net/?f=%20P%28z%3C1.13%29%20%3D%200.8708)
And the best option would be:
![0.8708](https://tex.z-dn.net/?f=%200.8708)
Rounded it is 11.7 cubic cm.
I think I know what your asking so the answer would be 27/30 and 28/30
Answer:
X=15
all you have to do is subtract 3 from 18 to get x
Answer: 0.395 km
Step-by-step explanation:
Let Martin distance from the hole be X
On first stroke, his golf ball traveled 4/5 of the distance to the hole. That is 4/5 X
On his second stroke, the ball traveled 79 meters and went into the hole
Total distance covered will be
X = 79 + 4/5X
X - 4/5X = 79
X - 0.8X = 79
0.2X = 79
X = 79/0.2 = 395 meters
How many kilometers from the hole was Martin when he started
X = 395/1000 = 0.395 km