Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
Answer:
X = 4
I hope this helps
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Answer:
(4,-1)
x=4
y=-1
Step-by-step explanation:
Multiple 1.65/100 which equals 14.4375
The add 14.4375 to 875 & round to the closest cent which is 889.44
Answer:
When f(n) = 4n and g(n) = n² + 2n, f(g(-6)) = 96.
Step-by-step explanation:
To evaluate f(g(-6)), first find g(-6).
g(n) = n² + 2n
Substitute value.
g(-6) = (-6)² + 2(-6)
Square -6. Remember that (-x)² = x²
g(-6) = 36 + 2(-6)
Multiply 2 and -6.
g(-6) = 36 - 12
Subtract 12 from 36.
g(-6) = 24.
Now knowing this, substitute that value into f(n).
f(g(-6)) = f(24)
f(n) = 4n
Substitute value.
f(24) = 4(24)
Multiply 4 and 24.
f(24) = 96.
