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3 years ago

How many centimeters are in 8 feet, given that 1 in. 2.54 cm.

Mathematics

2 answers:

sergejj [24]3 years ago

5 0

Answer:

243.84

Step-by-step explanation:

Since there are 12 inches in 1 foot, multiply 2.54 by 12

12 x 2.54 = 30.48

Since you are measuring 8 feet, multiply 30.48 by 8

30.48 x 8 =243.84

Delicious77 [7]3 years ago

3 0

Answer:

243.84

Step-by-step explanation:

We change feet to inches, and inches to cm.

1 ft = 12 in.

1 in. = 2.54 cm

8 ft * (12 in.)/(1 ft) * (2.54 cm)/(1 in.) = 243.84 cm

8 ft = 243.84 cm

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Please help Point L is located at coordinate-35

Gnoma [55]

The coordinate of the midpoint of line segment LT is determined as: -12.

<h3>How to Find the Coordinate of the Midpoint of a Line Segment?</h3>

The midpoint of a line segment is the point where the distance between the endpoints of the line segment are equidistant. The distance from that midpoint to each endpoint is the same.

Given the following:

Coordinate of point L is: -35
Coordinate of point T is: 11

Distance from point L to T = |-35 - 11| = 46 units.

Half of 46 units would be: 46/2 = 23 units.

This means that, both point L and point T are 23 units from the midpoint of segment LT.

Thus, the coordinate of the midpoint would be 23 units from -35 = -35 + 23 = -12

Or 23 units from the midpoint to point T = 11 - 23 = -12

Therefore, the coordinate of the midpoint of line segment LT is determined as: -12.

Learn more about the midpoint of a segment on:

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1 year ago

What are the missing numbers?

inna [77]

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The first box is 2.089

The second box is 2.095

Step-by-step explanation:

Between each line there is 1 thousandth added to the number.

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3 years ago

Simplify -2(x - 5) + 4(9 + x). -2x + 10 + 36 + 4x -2x - 10 + 36 + 4x 2x+ 26 2x + 46

Umnica [9.8K]

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Step-by-step explanation:

If your wanting me to check your work then yes you got it right the anwser is =2x+46.

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3 years ago

Read 2 more answers

A telephone survey uses a random digit dialing machine to call subjects. the random digit dialing machine is expected to reach a

yanalaym [24]

P( $r$ successes in $n$ trials) = ⁿ $C_{r}$ × $[P(Success)^{r}]$ × $[P(failure)]^{n-r}$

We have
$n=8$
$r=2$
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$P(Failure)=0.85$

Substitute these values into the formula, we have
P( 2 success in 8 trials) = ⁸C₂ × (0.15)² × (0.85)⁶
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3 years ago

A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of

Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

Step-by-step explanation:

Let X = time spent per week shopping online.

It is provided that the random variable X follows a Poisson distribution.

The probability function of a Poisson distribution is:

$P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...$

The average time spent per week shopping online is, λ = 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

$P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217$

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338$

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

$=\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922$

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0

4 years ago

How many centimeters are in 8 feet, given that 1 in. 2.54 cm.​

How many centimeters are in 8 feet, given that 1 in. 2.54 cm.