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zhenek [66]
3 years ago
11

Sixteen less than z gives six.

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0

<em><u>Algebra</u></em>

z-16=6

z=22

what your problem in word form is saying is that sixteen less from z equals out to 6.

GrogVix [38]3 years ago
6 0

Answer:

z = 22

Step-by-step explanation:

z - 16 = 6

z = 22

Hope this helped!

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A gift box is the shape of a rectangular prism. The box has a length of 24 centimeters, a width of 10 centimeters, and a height
Kamila [148]
Volume (V) is (=) Length (L) times (x) Width (W) times (x) Height (H) so V = L x V x H. 

Add the variables to the equation.
V = 24 x 10 x 13

Solve
V = 3120

So the volume of the gift box is 3120 cm
6 0
3 years ago
The perimeter of a square is 20. Find the length of the diagonal
klemol [59]

Answer:

d≈7.07

Step-by-step explanation:

Using the formulas

P=4a

d= \sqrt{2} a

Solving ford  

d= \sqrt{2} P/4=2·20 /4≈7.07107

8 0
3 years ago
Read 2 more answers
What are the coordinates of the x-intercept of the equation 2x - 3y = 8?
ludmilkaskok [199]

Answer:

(4;0)

Step-by-step explanation:

y=0

2x-3×0=8

2x=8

x=4

4 0
3 years ago
Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.Josiah has punch c
love history [14]

Let x be the number of weeks; therefore, the two linear equations are

\begin{gathered} T=2+7x \\ \text{and} \\ C=11+4x \end{gathered}

Where T stands for the punches on the tea punch card and C for the punches on the coffee punch card.

Solving by substitution. Set T=C, then

\begin{gathered} T=C \\ \Rightarrow2+7x=11+4x \\ \Rightarrow3x=9 \\ \Rightarrow x=\frac{9}{3}=3 \\ \Rightarrow x=3 \end{gathered}

Thus, substitute the value of x=3 into the first equation,

\begin{gathered} x=3 \\ \Rightarrow T=2+7\cdot3=23 \\ \Rightarrow T=23 \end{gathered}

Thus, after 3 weeks, Josiah will have the same number of punches on each card, and he will have 23 punches on each card.

6 0
1 year ago
Solve the equation using the quadratic formula. Enter each solution in simplest form.
sergeinik [125]

For this case we have the following quadratic equation:

x ^ 2-4x + 23 = 0

The solutions will be given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Where:

a = 1\\b = -4\\c = 23

Substituting the values we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}

We have two roots:

x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}

ANswer:

x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}

6 0
3 years ago
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