Answer:
(c) x = 2 and x = -8
Step-by-step explanation:
The rules of logarithms let you rewrite this as a quadratic equation. That equation will have two (2) potential solutions. We know from the domain of the log function that any negative value of x will be an extraneous solution.
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The rules of logarithms that apply are ...

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<h3>take antilogs</h3>
We can rewrite the equation so that only one logarithm is involved. Then we can take antilogs.

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<h3>solve the quadratic</h3>
Adding (6/2)² = 9 to both sides will "complete the square."
16 +9 = x² +6x +9 . . . . . . . add 9
25 = (x +3)²
±√25 = x +3 = ±5 . . . . . take the square root(s)
x = -3 ±5 = {-8, +2}
The two potential solutions are x = 2 and x = -8.
A= 50.27 because the formula is pi times radius squared
C= 24.13 because the formula is 2 times pi times radius
C. negative -1/4 < -(-2/3)
Explanation:
the doube negative on 2/3 turns it into a positive. since negative numbers are less than positive numbers, this is true
Answer:
x = 5/2
Step-by-step explanation:
2^x+4 = 2^3x-1
x + 4 = 3x - 1
3x - x = 4 + 1
2x = 5
x = 5/2
2 minutes per lap. I think