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AfilCa [17]
2 years ago
6

Please help me, I'm really confused. Given that a ∥ b and m∠6 is 1/8 of m∠4, find m∠4 and m∠6.

Mathematics
2 answers:
ASHA 777 [7]2 years ago
8 0

9514 1404 393

Explanation:

Finish the Given statement, make use of the relationships of angles and parallel lines, then finish the algebra.

__

2. m∠6 = (1/8)m∠4 . . . . Given

3. m∠6 + m∠4 = 180° . . . . 3. same-side interior angles are supplementary

4. m∠6 + 8·m∠6 = 180° . . . . 4. Substitution (from 2, above: 8·m∠6 = m∠4)

Here is the "algebra" that gets you to line 5:

4a. 9m∠6 = 180° . . . collect terms

4b. m∠6 = 20° . . . . . divide by 9

4c. m∠4 = 8·20° = 160° . . . use the same relation as in step 4

5. m∠6 = 20°, m∠4 = 160° . . . . Algebra

Andrews [41]2 years ago
5 0

m∠6=1/8m∠<u>4</u>

m∠6+m∠4=<u>180°</u>                S.S int. of parallel lines

m∠6+8·m∠<u>4</u>=180°

m∠6=20° m∠4=160°

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5 0
3 years ago
Select the correct answer from each drop-down menu. Trapezoid PQRS be inscribed in a circle because the .
prisoha [69]

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According to the statement

we have given that the Trapezoid PQRS be inscribed in a circle and we have to find the correct answer from the given data.

So, For this purpose, we know that the

The inscribed quadrilateral conjecture states that the opposite angle of any inscribed quadrilateral are supplementary to each other. That is, they have a sum of 180 degrees.

From the diagram given,

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Therefore, we can conclude that: trapezoid QPRS can be inscribed in a circle because its opposite angles are supplementary.

So, Trapezoid PQRS be inscribed in a circle because its opposite angles are supplementary.

Learn more about inscribed quadrilateral conjecture here

brainly.com/question/12238046

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Select the correct answer from each drop-down menu.

Trapezoid PQRS

4650

be inscribed in a circle because the

Reset

115⁰

Next

65°

For more understanding please see the image below.

#SPJ4

3 0
1 year ago
Can someone please check this?
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