Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
The statistical question would be B.
You can form 2 and then you have the odd one out.
First of all, we know that
Corporation A owns 3.2 × 10^5 acres
Corporation B owns 4×10^4 acres
Corporation C owns 4.3×10^5 acres
To compare which corporation owns the most land, we need to have the same unit of exponent which is 10^4, so we need to change Corporation A and Corporation C:
Corporation A: 3.2×10^5
Corporation A: 32×10^4
Corporation C: 4.3×10^5
Corporation C: 43×10^4
In this case, compare all three corporation. We see that Corporation C owns the most land.
Lastly,
To find “ How many times greater is corporation A’s land than corporation B’s land ", take:
Corporation A / Corporation B
=32×10^4/4×10^4
=32/4×10^4/10^4
=8×10^4-4
=8×10^0
=8×1
=8 times is your final answer. Hope it help!
