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3 years ago

Help me please! With my Algebra 2. :)

Mathematics

1 answer:

KIM [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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What type of triangle do i have if the angles are:15, 10,155

xenn [34]

Obtuse, accute, obtuse, acute, A.

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4 years ago

A figure is composed of a semicircle and a right triangle. Determine the area of the shaded region. Use 3.14 for π and round to

Aliun [14]

Answer:

$A=9.5\ ft^2$

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of triangle plus the area of semicircle

$A=\frac{1}{2}bh+\frac{1}{2}\pi r^{2}$

we have

$b=4\ ft$

Find the height of the right triangle applying the Pythagorean Theorem

$5^2=h^2+4^2$

$h^2=9\\h=3\ ft$

The radius of the semicircle is half the height of triangle

$r=3/2=1.5\ ft$

substitute in the formula

$A=\frac{1}{2}(4)(3)+\frac{1}{2}(3.14)(1.5)^{2}$

$A=6+3.5=9.5\ ft^2$

5 0

3 years ago

Read 2 more answers

In tuv y is centroid if yw=5b and ty=4b+14 find tw

stellarik [79]

your right Step-by-step explanation:

3 0

3 years ago

1-Describe the error in the way the calculation of the slope of the two points is set up and/or solved. Please be specific. Do n

Bad White [126]

Answer:

Please check explanations for answer

Step-by-step explanation:

Let’s have two points (5,10) and (15,20)

1. Let’s find the slope of these two points

Mathematically, the slope can be calculated using the formula;

m = (y2-y1)/(x1-x2)

So m = (20-10)/(5-15) = 10/-10 = -1

The error here is the formula used in calculating the slope

The formula should be;

m = (y2-y1)/(x2-x1) and not x1-x2

2. To calculate the slope correctly, we have;

m = (y2-y1)/(x2-x1)

So the slope will be;

m = (20-10)/(15-5) = 10/10 = 1

In the point slope form, the equation can be represented as;

y-y1 = m(x-x1)

Let’s use the point (5,10)

y- 10 = 1(x-5)

The above is the point slope form

using one of the points and the correct slope of the line

6 0

3 years ago

What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?

Anvisha [2.4K]

Answer:

$y=-\frac{3}{2}x-\frac{9}{2}$

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = $\frac{y_2-y_1}{x_2-x_1}$

m' = $\frac{1+1}{3-0}$

m' = $\frac{2}{3}$

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × $\frac{2}{3}$ = -1

m = $-\frac{3}{2}$

Equation of the perpendicular line will be,

$y=-\frac{3}{2}x+b$

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)

0 = $-\frac{3}{2}(-3)+b$

b = $-\frac{9}{2}=-4.5$

Equation of the line will be,

$y=-\frac{3}{2}x-\frac{9}{2}$

3 0

3 years ago