All categories

3 years ago

SIMPLIFY (4-74+7) A. 223 B. 9 27 C. 9+2/7 D. 9

Mathematics

1 answer:

sesenic [268]3 years ago

6 0

Answer:

The correct option is D.

Step-by-step explanation:

The given expression is

$(4-\sqrt{7})(4+\sqrt{7})$

Difference of two squares property:

$a^2-b^2=(a+b)(a-b)$

Using the above property, the given expression can be written as

$(4)^2-(\sqrt{7})^2$

Applying square we get

$16-7$

$9$

Therefore the correct option is D.

You might be interested in

1. A bag contains four green gumballs, three blue gumballs, and two red gumballs, all the same size and shape.

Dahasolnce [82]

Answer:

Step-by-step explanation:

a. P (red) = 2/9

b. P (blue) = 3/9 = 1/3

c. P (green) = 4/9

d. Green, because out of the three types of gumballs, the green gumballs are more in number, therefore, it is the one you are most likely to get.

7 0

2 years ago

Write expression that is equivalent to 1/4 a -3

miskamm [114]

4-2=2 that is the answer to

8 0

2 years ago

Which statement is correct?

vladimir2022 [97]

It's C) The range and domain of the graph are the same.
I think D is correct too.

7 0

3 years ago

Read 2 more answers

On a scale drawing of a museum to water fountains are 10 inches apart. the actual distance between them is 400 ft. on the same d

KatRina [158]

400 / 10 = 40

so every 1 inch = 40 feet

3.125 * 40 = 125 feet between the exhibits

please mark brainliest

7 0

3 years ago

Use the table of values below to select the correct statement.

quester [9]

Answer:

Linear function with rate of change/growth = 2.5, which agrees with the fourth statement listed in the answers options.

Step-by-step explanation:

Notice that both columns of reported x and y values are increasing.

Then examine how the given x-values increase:

-2, 2, 6, 10, 14 (in steps of 4 units)

and how their corresponding y-values increase:

-2, 8, 18, 28, 38 (in steps of 10 units)

therefore, if we do the rate of change for any pair $(x_1,y_1)$ and $(x_2,y_2)$ , we get the following constant rate of change:

$\frac{y_2-y_1}{x_2-x_1} = \frac{10}{4} =2.5$

Given that this relationship is valid for any pair of (x,y) values. we conclude that the rate of increase is constant, and therefore we are in the presence of a linear function, whose rate of change is 2.5

8 0

3 years ago