K-3=-2k+5
3k=8
k=(3/8)
Neither
2x²+13x-45 =(x+9)(2x-5)
3/(x+9)=[3(2x-5)]/[(x+9)(2x-5)]=(6x-15)/(2x²+13x-45)
Step-by-step explanation:
![\frac{16 {x}^{4} - 28 {x}^{3} + 8x }{4x} = \\ \frac{16 {x}^{4} }{4x} - \frac{ 28{x}^{3} }{4x} + \frac{8x}{4x} = \\ ( \frac{16}{4} \times \frac{ {x}^{4} }{x} ) - ( \frac{28}{7} \times \frac{ {x}^{3} }{x} ) + ( \frac{8}{4} \times \frac{x}{x} ) = \\ 4 {x}^{3} - 7 {x}^{2} + 2](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%20%7Bx%7D%5E%7B4%7D%20-%2028%20%7Bx%7D%5E%7B3%7D%20%20%2B%208x%20%7D%7B4x%7D%20%20%3D%20%20%5C%5C%20%20%5Cfrac%7B16%20%7Bx%7D%5E%7B4%7D%20%7D%7B4x%7D%20%20-%20%20%5Cfrac%7B%2028%7Bx%7D%5E%7B3%7D%20%7D%7B4x%7D%20%20%2B%20%20%5Cfrac%7B8x%7D%7B4x%7D%20%20%3D%20%5C%5C%20%28%20%5Cfrac%7B16%7D%7B4%7D%20%20%5Ctimes%20%20%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B4%7D%20%7D%7Bx%7D%20%29%20-%20%28%20%5Cfrac%7B28%7D%7B7%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%7Bx%7D%5E%7B3%7D%20%7D%7Bx%7D%20%29%20%2B%20%28%20%5Cfrac%7B8%7D%7B4%7D%20%20%5Ctimes%20%20%5Cfrac%7Bx%7D%7Bx%7D%20%29%20%3D%20%5C%5C%204%20%7Bx%7D%5E%7B3%7D%20%20-%207%20%7Bx%7D%5E%7B2%7D%20%20%2B%202)
Answer:
ab = 49
abc=253
bac=156
acb=311
Step-by-step explanation:
The volume of the bin is the amount of books it can contain.
455 books will fit in the bin
The dimension of the book is given as:
![\mathbf{Book = 0.75ft, 0.75ft, 0.25ft}](https://tex.z-dn.net/?f=%5Cmathbf%7BBook%20%3D%200.75ft%2C%200.75ft%2C%200.25ft%7D)
The dimension of the bin is given as:
![\mathbf{Bin = 4ft, 4ft, 4ft}](https://tex.z-dn.net/?f=%5Cmathbf%7BBin%20%3D%204ft%2C%204ft%2C%204ft%7D)
Start by calculating the volume of the book
![\mathbf{Book = 0.75ft \times 0.75ft\times 0.25ft}](https://tex.z-dn.net/?f=%5Cmathbf%7BBook%20%3D%200.75ft%20%5Ctimes%200.75ft%5Ctimes%200.25ft%7D)
![\mathbf{Book = 0.140625ft^3}](https://tex.z-dn.net/?f=%5Cmathbf%7BBook%20%3D%200.140625ft%5E3%7D)
Next, calculate the volume of the bin
![\mathbf{Bin = 4ft \times 4ft \times 4ft}](https://tex.z-dn.net/?f=%5Cmathbf%7BBin%20%3D%204ft%20%5Ctimes%204ft%20%5Ctimes%204ft%7D)
![\mathbf{Bin = 64ft^3}](https://tex.z-dn.net/?f=%5Cmathbf%7BBin%20%3D%2064ft%5E3%7D)
So, the number of books (n) is:
![\mathbf{n = \frac{Bin}{Book}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bn%20%3D%20%5Cfrac%7BBin%7D%7BBook%7D%7D)
This gives
![\mathbf{n = \frac{64ft^3}{0.140625ft^3}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bn%20%3D%20%5Cfrac%7B64ft%5E3%7D%7B0.140625ft%5E3%7D%7D)
Cancel out the units
![\mathbf{n = \frac{64}{0.140625}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bn%20%3D%20%5Cfrac%7B64%7D%7B0.140625%7D%7D)
![\mathbf{n = 455.11}](https://tex.z-dn.net/?f=%5Cmathbf%7Bn%20%3D%20455.11%7D)
Remove the decimals
![\mathbf{n = 455}](https://tex.z-dn.net/?f=%5Cmathbf%7Bn%20%3D%20455%7D)
Hence, 455 books will fit in the bin
Read more about volumes at:
brainly.com/question/15861918