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ra1l [238]
3 years ago
13

Which terms of the AP: 213, 207, 201… is its last positive term?

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer: the last pos term is 3

Details:

213

207

201

195

189

183

177

171

165

159

153

147

141

135

129

123

117

111

105

99

93

87

81

75

69

63

57

51

45

39

33

27

21

15

9

3

-3


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11/15=.7333333 so the one with the line above the 3 only
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If 3x - 2 = 13, what is the value of x?<br>0-5<br>• 5<br>0 -3.7<br>0 3.7<br>​
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Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing four red marbles, four green ones, two
Rainbow [258]
The answer to this question would be: 85/99

In this question, Suzan is taking 8 marble from a bag containing 4 red marbles, 4 green ones, 2 white ones, and 2 purple ones. The total marble in the bag should be: 4+4+2+2= 12. The question is how much the probability to get <4 red marble. In this question, the green, white and purple is not specified so you can join them into not red group. It will be easier to find the probability of "have all the red one" which mean Suzan take 4 red marble and 4 not-red marble<span>

Ways to take 8 marble out of 12=12C5= 12!/4!8!= </span>495
Ways to take 4 red marble out of 4= 4C4= 1
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Probability to <span>have all the red ones= 1*70/495= 14/99
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Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
1 year ago
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