A manufacturer knows that their items have a normally distributed length, with a mean of 10 inches, and standard deviation of 1.
1 answer:
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We have to find the values of F.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.
Substitute, x = 1/2
F(1/2) + F(−1) = −1/2.
We still are not getting the required value,
therefore,
Substitute x = −1
As, F(2) +F(−1) = 0.
now we have three equations in three unknowns, which we can solve.
It turns out that:
F(2) = 3/4
F(3) = 17/12
F(4) = 47/24
and
F(5) = 99/40
Setting
g(x) = 1 − 1/x
and using
2 → 1/2
to denote
g(2) = 1/2
we see that :
x → 1 - 1/x → 1/(1-x) →x
so that:
g(g(g(x))) = x.
Therefore, whatever x 6= 0, 1 we start with, we will always get three equations in the three “unknowns” F(x), F(g(x)) and F(g(g(x))).
Now solve these equations to get a formula for F(x)
As,
h(x) = (1+x)/(1−x)
which satisfies h(h(h(h(x)))) = x
Now, mapping x to h(x) corresponds to rotating the circle by ninety degrees.
In this case. F is unlikely to be a polynomial.
But the problem is, we can’t calculate the values of F directly.
There is no real value of x for which x = x−1 x because F isn’t defined at 0 or 1. so,
substituting x = 2.
F(2) + F(1/2) = 3.
Substitute, x = 1/2
F(1/2) + F(−1) = −1/2.
We still are not getting the required value,
therefore,
Substitute x = −1
As, F(2) +F(−1) = 0.
now we have three equations in three unknowns, which we can solve.
It turns out that:
F(2) = 3/4
F(3) = 17/12
F(4) = 47/24
and
F(5) = 99/40
Setting
g(x) = 1 − 1/x
and using
2 → 1/2
to denote
g(2) = 1/2
we see that :
x → 1 - 1/x → 1/(1-x) →x
so that:
g(g(g(x))) = x.
Therefore, whatever x 6= 0, 1 we start with, we will always get three equations in the three “unknowns” F(x), F(g(x)) and F(g(g(x))).
Now solve these equations to get a formula for F(x)
As,
h(x) = (1+x)/(1−x)
which satisfies h(h(h(h(x)))) = x
Now, mapping x to h(x) corresponds to rotating the circle by ninety degrees.
Answer:
(a) <em>H₀</em>: <em>μ</em> ≤ 10. vs. <em>Hₐ</em>: <em>μ</em> > 10.
(b) The test statistic value is 1.86.
(c) The critical value to test the phone manufacturer's claim is 1.301.
(d) The battery life of the new touch screen phone is not more than 10 hours.
Step-by-step explanation:
In this case we need to determine the significance of the claim made by the phone manufacturer, that the battery life of the new touch screen phone is more than twice as long as that of the leading product.
The information provided is:
(a)
The hypothesis can be defined as follows:
<em>H₀</em>: The battery life of the new touch screen phone is not more than 10 hours, i.e. <em>μ</em> ≤ 10.
<em>Hₐ</em>: The battery life of the new touch screen phone is more than 10 hours, i.e. <em>μ</em> > 10.
(b)
As the population standard deviation is not provided, we will use a <em>t</em>-test for single mean.
Compute the test statistic value as follows:
The test statistic value is 1.86.
(c)
The significance level of the test is, <em>α</em> = 0.10.
The degrees of freedom will be:
Compute the critical value as follows:
*Use a <em>t</em>-table for the value.
Thus, the critical value to test the phone manufacturer's claim is 1.301.
(d)
Decision rule:
If the test statistic value is less than the critical value then the null hypothesis will be rejected and vice-versa.
t = 1.86 > t₀.₁₀, ₄₄ = 1.30
The calculated <em>t</em>-value of the test is more than the critical value.
The null hypothesis will not be rejected.
Thus, it can be concluded that the battery life of the new touch screen phone is not more than 10 hours.