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3 years ago

Find the inverse relationship of the function y=2x+5

Mathematics

2 answers:

LekaFEV [45]3 years ago

6 0

Answer:

Duke is a very good team and

daser333 [38]3 years ago

3 0

Answer:

y=x-5/2

Step-by-step explanation:

Swap y and x

x=2y+5

since a function has to be in the form y=mx+c

take 5 to the other side in order to remain with 2y then divide both sides by 2

x-5/2=y

y=x-5/2

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Simplify the question above

andrey2020 [161]

Answer:

$1 + \frac{3}{x}$

Step-by-step explanation:

1) Rewrite x² - 9 in the form a² - b² where, a = x and b = 3.

$\frac{ {x}^{2} - {3}^{2} }{ {x}^{2} - 3x}$

2) use difference of squares: a² - b² = ( a + b ) (a - b).

$\frac{(x + 3)(x - 3)}{ {x}^{2} - 3x}$

3) Factor out the common term x.

$\frac{(x + 3)(x - 3)}{ x(x - 3)}$

4) Cancle out x - 3 .

$\frac{x + 3}{x}$

5) Simplify.

$1 + \frac{3}{x}$

Therefor, the answer is 1 + 3/x.

6 0

3 years ago

Read 2 more answers

I know how to do this but I just want to spend some points :)

Lunna [17]

Answer:

domain: all real numbers

range: y<-2

Step-by-step explanation:

I think its correct but already know the answer sooo yea

7 0

3 years ago

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;