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3 years ago

HELP ASAP!!!!!! BRAINLIEST

Mathematics

2 answers:

ELEN [110]3 years ago

6 0

Answer:

I don't know if this is ganna help at all

0- y=54

1 - y =6

2- y=18

3- y= 54

mote1985 [20]3 years ago

3 0

Answer:

the base is 3

Step-by-step explanation:

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Simplify: 6(5x - 2) - (3x - 4)

Sloan [31]

Answer:

$27x-8$

Step-by-step explanation:

$6(5x-2)-(3x-4)\\30x-12-3x+4\\27x-8$

7 0

3 years ago

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MArishka [77]

Answer:

$\huge\boxed{\sf Option \ 1}$

Step-by-step explanation:

People surveyed = 42

People who approved = 25

<u>So, the sample is:</u>

25 residents who approve.

<u>And population:</u>

42 residents surveyed.

$\rule[225]{225}{2}$

3 0

2 years ago

PC-CSIL

pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: $-c = ax^2 + bx$

The given equation is: $0 = ax^2 + bx + c$

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

$0-c = ax^2 + bx + c-c$

$-c = ax^2 + bx$

So, The equality used is Subtraction property of equality

Option A is correct.

Keywords: Solving Quadratic Equations

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5 0

3 years ago

A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtain

slega [8]

Answer: 8359

Step-by-step explanation:

The formula for sample size needed for interval estimate of population proportion :-

$n=p(1-p)(\frac{z_{\alpha/2}}{E})^2$

Given : The significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}}=z_{0.025}=\pm1.96$

Previous estimate of proportion : $p=0.32$

Margin of error : $E=0.01$

Now, the required sample size will be :-

$n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx8359$

Hence, the required sample size = 8359

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3 years ago

Find the average of: 15, 8, -22, 24, -9, -18, 16

trasher [3.6K]

The average is 2. To find the average you add all the numbers then divide the sum by the total amount of numbers.

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4 years ago

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